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(((4*y^3)/8)*z^6)^5 = 0
1/32*y^15*z^30 = 0
x należy do R
x in (-oo:+oo)
| 6y-15y-19=-19 | | X+2.9=8.6 | | y-2=-4(x-10) | | (2x-3)+(7x+4)= | | 10(6.6)+15= | | y-5=-9(x+1) | | 17-3x=2+7x | | 2x-8yi=-2+4yi | | 5(x-2)=16-x | | y-3=16(x-6) | | 104=12x+w | | -1/105m=8 | | 40-73d-80-9d+2+6d= | | y+1=-10(x+1) | | -2(y-w)-(w-6y)= | | -8045=5k | | 19=13 | | N-15=-3 | | x^2+9-5x=0 | | y+3=5(x-4) | | ln(6x+3)-ln(9x)=5 | | 1/2=x/17 | | 1/14a=-17 | | x^2+9-5x=y | | 2x+1=3x-29 | | x+(2x-3)+(x-7)=12 | | y-6=-7(x+9) | | 201.9y=1615.2 | | 9x+2+3x+10=180 | | 12.50=15 | | f(5)=3.3x-1 | | y=av-ac^5 |